수열의 합

/*
수열의 합: N <= 1,000,000,000
2 <= L <= 100
a: 1항
d = 1(등차)
*/

#include <iostream>
#define MAX_N 1,000,000,000
using namespace std;

class sequence {
private:
	int s = 0;
	int l = 0;
	int a = 0;
	int max = 0;
public:
	sequence() {
		scanf("%d %d", &s, &l);
	}

	void seq() {
		int cntnum;
		if (s > MAX_N || l < 2 || l > 100)
		{
			return;
		}

		while (1) {
			a = ((2 * s) + (l - l*l)) / (2 * l);
			max = a;
			cntnum = a + 1;
			if (a < 0) {
				a = -1;
				return;
			}

			for (int i = 1; i < l; i++)
			{
				max = max + cntnum;
				cntnum++;
				if (max == s && i == l - 1) {
					return;
				}
			}
			l++;
			if (l > 100)
			{
				a = -1;
				return;
			}
		}
	}

	void show()
	{
		if (a < 0) {
			cout << "-1" << endl;
			return;
		}
		for (int i = 1; i < l; i++)
		{
			cout << a << " ";
			a++;
		}
		cout << a << endl;
		return;
	}
};

int main() {
	sequence s1;
	s1.seq();
	s1.show();
}